Question

5 table and 9 chairs cost 71, where as 9 table and.
3 Chairs cost 75
what will be the
cost 6 Chris and 4 tables ?​

Answer 1

Answer:

Rs.52

Step-by-step explanation:

Let the cost of 1 chair and 1 table be Rs. X and Y respectively.

Cost of 1 chair = x

9 chairs cost = Rs.9x

Then, 5 tables cost = Rs. 5y

9x + 5y = 71

9x = Rs.71 - 5y

3 × 3x = 71-5y

3x = 71 -5y/3 ........equation 1

Now, 3 chairs cost = 3x

9 tables cost = 9y

3x + 9y = Rs. 75

Computing value of 3x from equation 1, we get:

71-5y/3 + 9y = 75

71 - 5y + 27y/3 = 75

71 + 22y/3 = 75

71 + 22y = 75×3

71 + 22y = 225

22y = 225-71

22y = 154

y = 154/22 = 7

So cost of 1 table = Rs.7

9x + 5y = 71

9x + 5×7 = 71

9x = 71-35

x = 36/9

x = 4

Hence cost of 1 chair = Rs. 4 and 1 table = Rs.7

Cost of 6 chairs and 4 tables = 6×4 + 4×7

= Rs. 24 + 28

= Rs. 52.

Hope it helps you.