Question

5 tan^2A-5 sec^2A + 1 is equal to(a) 6(b) 5(c) 1(d)-4​

Answer 1

Option $\blue{\underline{\bf\green{ \quad (d) - 4 \quad }}}$ is the right answer.

We have,

$\quad 5 { \tan}^{2} a - 5 { \sec }^{2} a + 1 \\ \\ = - 5( { \sec}^{2} a - { \tan}^{2} a) + 1 \\ \\ = - 5(1) + 1 \quad{ \large{ \red{ \longmapsto}}}[ \because { \sec}^{2} \theta - { \tan}^{2} \theta = 1] \\ \\ = - 5 + 1 \\ \\ = - 4$

$\mid \underline{\underline{\LARGE\bf\green{Brainliest \: Answer}}}\mid$