Math, asked by rakeshpilania59662, 8 months ago

5.Test the divisibility of the following numbers by 6:

a. 56832

b. 86120

c. 97530​

Answers

Answered by srivastavamk840
1

Step-by-step explanation:

9472 for the first one

not divisible clearly

16255 for the third one

Answered by Anonymous
2

Divisibility test of 6 is

IF the given no. Is divisible by 2&3 then it is divisible by 6.

A. 56832

= It is divisible by 2 as the once place is divisible by 2. As the sum of the above no. Is 24 so, it is divisible by 3.

Therefore, it is divisible by 6

b. 86120

= It's is divisible by 2 as the once place is 0. Also as the sum of the above no. Is 17 so, it's is not divisible by 3.

Therefore, it is not divisible 6

c. 97530

= it is divisible by 2 as the once place is 0. Also as the sum of the above no. Is 24 so, it is divisible by 3 .

Therefore it is divisible by 6.

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