5 th question of rd sharma pls solve it(polynomials. ex2.1)
Attachments:
Answers
Answered by
1
see..1/alph+1/beta = (alpha+beta)/alpha.beta....(by taking LCM)
so now ya can get the value of alpha+beta=1
&alpha.beta=-4
now...put this value into the above and you will get the answer.....!
so now ya can get the value of alpha+beta=1
&alpha.beta=-4
now...put this value into the above and you will get the answer.....!
Answered by
0
Hey !!
solution :-
f(x) = x² - x - 4
•°•
so , sum of roots = -(cofficient of x/cofficient of x²)
so ,
------1)
and
product of roots = constant term /cofficient of x²
hence ,
= -4 ----------2)
now .from
from question ..
1/
=>
-1 /4 -4
=> 1 -16/4 = -15/4 Answer
*************************************
Hope it helps you !!!
@Rajukumar111
solution :-
f(x) = x² - x - 4
•°•
so , sum of roots = -(cofficient of x/cofficient of x²)
so ,
------1)
and
product of roots = constant term /cofficient of x²
hence ,
= -4 ----------2)
now .from
from question ..
1/
=>
-1 /4 -4
=> 1 -16/4 = -15/4 Answer
*************************************
Hope it helps you !!!
@Rajukumar111
Similar questions