Question

5. The active mass of 127 mg of Iodine vapour present in 2 liter vessel, is (A) 0,5x10-3 (B) 0.5x10-4 (C) 2.5x10-3 (D) 2.5x10-4​

Answer 1

Refer to the attachment!!

Answer 2

Answer:

Active mass of 64g of HI in a two litre flask can be measured by:

As we know,

H = 1 g/mol

I = 127 g/mol

Active mass = 64/(128×2)

Where molecular weight is 128 and volume is 2 litre.

By calculating, active mass comes out to be 0.25.

Explanation:

Hope it helps u dude!!✌️