Question

5. The altitude of a right triangle is 7 cm less than its base. If the hypotenuse is 13 cm, find the other two sides.​

Answer 1

Answer:

Let x be the base of the triangle, then the altitude will be (x−7).

By Pythagoras theorem,

x2+(x−7)2=(13)2

2x2−14x+49−169=0

2x2−14x−120=0

x2−7x−60=0

x2−12x+5x−60=0

(x−12)(x+5)=0

x=12,x=−5

Since the side of the triangle cannot be negative, so the base of the triangle is 12cm and the altitude of the triangle will be 12−7=5cm.

Answer 2

Answer is given in attachment.