Question

5. The angular velocity of a particle moving along a circle of radius 50 cm is increased in 5 minutes from 100 revolutions per minute to 400 revolutions per minute. Find (i) angular acceleration and (ii) linear acceleration.​

Answer 1

Explanation:

Initial angular velocity of particle is ω

1

=

60

200π

rads

−1

Final angular velocity of particle is ω

2

=

60

800π

rads

−1

angular acceleration α=

T

ω

2

−ω

1

where T is total time which is equal to 5×60=300sec

⇒α=

300

60

800π

−

60

200π

=

300

10π

=

30

π

rads

−2

Tangential acceleration of the particle a=αr

where r is radius of the circle, r=

2

1

m

⇒a=

30

π

×

2

1

=

60

π

ms

−2

mark as brainliest