Question

5. The L.C.M. of 12x²y3z2 and 18x4y2z>is​

Answer 1

LCM of

${12}^{2} {y}^{2} {z}^{2} \: \: and \: \: 18 {x}^{4} {y}^{2} z$

${12}^{2} {y}^{2} {z}^{2} \: = 2 \times 2 \times 3 \times 2 \times 2 \times 3 \times y \times y \times z \times z$

$2 \times 3 \times 3 \times x \times x \times x \times x \times y \times y \times z$

Taking the common multiples

$= 2 \times 3 \times 3 \times y \times z$

$= 18yz$

So the LCM is 18yz

Answer 2

Answer:

LCM of

{12}^{2} {y}^{2} {z}^{2} \: \: and \: \: 18 {x}^{4} {y}^{2} z12

2

y

2

z

2

and18x

4

y

2

z

{12}^{2} {y}^{2} {z}^{2} \: = 2 \times 2 \times 3 \times 2 \times 2 \times 3 \times y \times y \times z \times z12

2

y

2

z

2

=2×2×3×2×2×3×y×y×z×z

2 \times 3 \times 3 \times x \times x \times x \times x \times y \times y \times z2×3×3×x×x×x×x×y×y×z

Taking the common multiples

= 2 \times 3 \times 3 \times y \times z=2×3×3×y×z

= 18yz=18yz

So the LCM is 18yz

Step-by-step explanation:

may it helps you