Question

5. The minute hand of a large clock is 0.5 m long. (a)
What is the linear speed of the tip in ms-'? (b) What
is the centripetal acceleration of its tip?
Ans: a) v = 0.0524 ms b) a. -0.0055 ms
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Answer 1

Answer:

a)0.0524ms. b)a.-0.0055ms

Explanation:

Speed= 0.5×2pi÷3600

speed=8×10^-5 m/s

acceleration= r×w^2

acceleration=0.5× (2pi÷3600)^2

acceleration=1.5×10^-6 m/secondsquare

1.0

Answer 2

AnswThe angular speed of the minute's hand

ω = 2π 60×60 = π1800 radian second

a)the linear speed of minute's hand=>

v =ω r =π 1800× 0.5= π 3600 m/s.

b)centripetal acceleration of minute's hand=>

v2r=π3600×π36000.5=

π21800×3600= π26480000m/s^2. n: