Question

5. The number moles in 400g CaCO3 is (Hint GAM Ca=40g, C=12g, O=16g) ​

Answer 1

400/68

Explanation:

because no. of moles=given mass/molar mass

Answer 2

Answer:

Let me help you for this question.....

Given: Garm molecular weight of  $CaCO_{3}$ = 400g

=> At first we have to calculate the actual Gram molecular weight of CaCO3

=> Actual GAM( Gram Molecular Weight) = 40 + 12 + 16 × 3 = 100g

FORMULA USED ( IMPORTANT ) :

No. of moles = Given Gram Molecular Weight / Actual GAM

=> No. of moles = 400/100 = 4 moles

Hope you've understood the answer....

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