5. The present age of a father is 100% more than the present age of his son. 10 years ago, the age of father is 200% more than as that of his son. What will be the ratio of the ages of father and son after 15 years from now?
Answers
Given info : The present age of a father is 100% more than the present age of his son. 10 years ago, the age of father is 200% more than as that of his son.
To find : the ratio of the ages of father and the son after 15 years from now.
solution : let present age of son is x
so present age of father = x + 100% of x = 2x
10 years ago,
father's age = (2x - 10)
son's age = (x - 10)
but father's age = son's age + 200% of son's age
⇒2x - 10 = x - 10 + 2(x - 10) = 3x - 30
⇒10 = x
present age of son = 10 years
and present age of father = 20 years
15 years after,
son's age = 10 + 15 = 25 years
father's age = 20 + 15 = 35 years
therefore the ratio of ages of father and his son =. 35 : 25 = 7 : 5
Answer:
11:7
Step-by-step explanation:
let present age of the son is x
so present age of father = x + 100% of x = 2x
10 years ago,
father's age = (2x - 10)
son's age = (x - 10)
but father's age = son's age + 200% of son's age
⇒2x - 10 = x - 10 + 2(x - 10) = 3x - 30
⇒10 = x
so the age of son before 10 years is 10
so the present age is 20.
the father's age will be 100%of 20 so 40.
after 15 years their ages will be
father 40+15=55
son 20+15= 35
and their ratio will be 11:7