Question

EXERCISE
LEVEL-1
Find the area of a triangle whose sides are respectively 150 cm 120 cm and 200
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Answer 1

Answer:

18,00,000

Step-by-step explanation:

Area of triangle = 1/2*base*height1*height2

=1/2*200*150*120

= 1*100*150*120

= 18,00,000

Answer 2

Answer :

The area of the triangle is 8966.57 cm²

Step-by-step explanation :

To Find,

• The area of the triangle

Solution,

Given that,

• Sides of the triangle 150 cm, 120 cm and 200 cm

Let us assume,

• a = 150cm
• b = 120cm
• c = 200 cm

Therefore,

$\bf{Semi-perimeter} = \sf{\dfrac{a + b + c}{2}} \\ \\ = \sf{\dfrac{150 + 120 + 200}{2}} \\ \\ = \sf{\dfrac{470}{2}} \\ \\ \sf{ = 235}$

Now, Area of the triangle, by applying heron's formula

$\bf{Area \: \: of \: \: triangle} = \sf{ \sqrt{s(s - a)(s - b)(s - c)}} \\ \\ = \sf{ \sqrt{235(235 - 150)(235 - 120)(235 - 200)}} \\ \\ = \sf{ \sqrt{235(85)(115)(35)}} \\ \\ = \sf{ \sqrt{235 \times 85 \times 115 \times 35}} \\ \\ = \sf{ \sqrt{80399375}} \\ \\ \sf{= {8966.57cm}^{2}} \: \: \bigstar$

Hence, the area of the triangle is 8966.57 cm².