Question

5. The present age of two brothers are in the ratio of 3:4. Five years back their ages were in the
ratio of 5 : 7. Find their present ages.
[Ans. 30 years and 40 years)
​

Answer 1

Answer: x=40(1st bro)

y=30(2nd bro)

Step-by-step explanation:

Answer 2

Step-by-step explanation:

Let the present age of the two brothers be 3x years and 4x years.

5 years ago, the age of the two brothers were (3x - 5) years and (4x -5) years.

According to the problem,

(3x - 5):(4x - 5) = 5:7

$=>\frac{3x-5}{4x-5}=\frac{5}{7}\\=>21x-35=20x-25\\=>21x-20x=35-25\\=>x=10$

∴ Present age of the two brothers are (3×10) = 30 years and (4×10) = 40 years.

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