Math, asked by bharti3718, 9 months ago

Find the total no. Of 6 digit number in which all and only odd digit appear

Answers

Answered by Irfan1729
1

Answer:

15625

Step-by-step explanation:

good morning

Answered by pansumantarkm
1

Step-by-step explanation:

∵ Since there are only five odd digit {1,3,5,7,9}

So, to make a 6 digit number using the odd digits one no should be repeated.

So in the 6 digit number all 6 places can be filled by the 6! ways.

Selection for repeated digit we can select it ⁵C₁ ways = 5 ways

∴ Required total number of 6 digit number is 5*(6!/2!) = 1800 [∵ one digit is repeated 2 times]

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