Question

5. The radii of curvature of the two faces of a convex
lens are 0.10 m and 0.15 m respectively. If the focal
length of the lens is 0.12 m, find the refractive index
of the material of the lens.
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Answer 1

Answer: u= 1.5

Explanation:

1/f = (u'/u -1) (1/R1 - 1/R2)

100/12= (u'/1 - 1) (100/10 -(- 100/15)). (u air =1)

25/3 = (u' -1)(10-(-20/3))

25/3= (u'-1) (30+20/3)

25/3=(u'-1)(50/3)

25/3 x 3/50 = u'-1

1/2 = u'-1

1/2 + 1 = u'

3/2 = u'

u'= 1.5

Answer 2

Answer:

1.5

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