5. The sides of an equilateral triangle are
(6x + 3y) cm, (8x + 9y – 5) cm and (10x + 12y -
8) respectively. Find the length of each side.
[Hint. Take 6x + 3y = 8x + 9y - 5 and
8x +9y - 5 = 10x + 12y - 8 as two equations.)
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Answered by
8
Answer:let a=b=c are the sides of triangle
(6x+3y)=(8x+9y-5)
2x+6y=5 first equation
6x+3y=10x+12y-8
4x+8y=8 second equation
multiplying equation first with -2 and then add with equation second
We get -4y=-2
so,y=1/2
now putting the value of y in equation second
we get 4x+4=8
4x=4
X=1
6×1+3×1/2=15/2
so, each side of the triangle is 15/2 cm
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Answered by
7
Answer:
The sides of an equilateral triangle are(6x + 3y)cm, (8x + 9y – 5) cm and (10x + 12y -8) respectively. Find the length of each side.[Hint. Take 6x + 3y = 8x + 9y – 5 ...
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