Question

5. The sides of triangle are 11 cm,6 cm and 15 cm. Find its area using Heron's Formula .
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Answer 1

Answer:

$Area \: of \: triangle = 20 \sqrt{2} {cm}^{2}$

Step-by-step explanation:

$a = 11cm,b = 6cm,c = 15cm \\ s = \frac{a + b + c}{2} = \frac{11 + 6 + 15}{2} = \frac{32}{2} = 16 \\ Area \: of \: triangle \\ = \sqrt{s(s - a)(s - b)(s - c)} \\ = \sqrt{16(16 - 11)(16 - 6)(16 - 15)} \\ = \sqrt{16 \times 5 \times 10 \times 1} \\ = \sqrt{2 \times 2 \times 2 \times 2 \times 2 \times 5 \times 5} \\ = 2 \times 2 \times 5 \times \sqrt{2} \\ = 20 \sqrt{2} {cm}^{2}$