Math, asked by vikasbajpai80, 4 months ago

the difference between ages of ravi and geeta is 10 years. if 5 years earlier ravi was twice as old as geeta, find there present age​

Answers

Answered by TheBrainliestUser
171

Answer:

Their present ages are:

  • Ravi's age = 25 years
  • Geeta's age = 15 years

Step-by-step explanation:

Given that:

  • The difference between ages of Ravi and Geeta is 10 years.
  • 5 years earlier Ravi was twice as old as Geeta.

To Find:

  • Their present ages.

Ravi is greater than Geeta as 5 years earlier Ravi was twice as old as Geeta.

Let us suppose:

  • The age of Ravi be S years.
  • Then Geeta's age will be (S - 10) years.

5 years earlier their ages:

  • Ravi's age = (S - 5) years
  • Geeta's age = 2(S - 10 - 5) years

Finding their present ages:

  • According to the question,

⇒ (S - 5) = 2(S - 10 - 5)

⇒ S - 5 = 2S - 20 - 10

⇒ 2S - S = 20 + 10 - 5

⇒ S = 25

Their ages present are:

  • Ravi's age = S = 25 years
  • Geeta's age = (S - 10) = (25 - 10) = 15 years

Anonymous: Perfect! :D
Answered by Anonymous
96

Given :-

Difference between ages of ravi and Geeta is 10 years

5 years earlier ravi was twice as old as geeta

Solution :-

Let the present age of Ravi be x and  Geeta's age will be (x - 10) years.

Now

After 5 years

age of Ravi's  = (x - 5) years

age of Geeta's age = 2(x - 10 - 5) years

(x - 5) = 2(x - 10 - 5)

Removing brackets\\

x- 5 = 2x - 20 - 10

2x - x = 20 + 10 - 5

x = 20 + 5

x = 25

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