Question

5. The sum of four consecutive multiples of 7 is 294. Find these multiples.
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Answer 1

Answer:

let's suppose four multiples are=( n), (n+1),(n+2),(n+3).

than they are the multiple of 7 than =(7n), 7(n+1), 7(n+2), 7(n+3).

than, according to question, =

(7n) +(7n+14)+(7n+21)+(7n+28)=294

than,. 28n +42= 294.

28n= 294-42

n= 252/28

hence, n= 9.

at Last, n= 7×9 = 63.

n+1= 7(9+1)= 70.

n+2 = 7 (9+2) = 77.

n+3. = 7 ( 9+3) = 84. (ANS).

CHECK OUT:-

☑️ 63+70+77+84 = 294.

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Answer 2

Answer:

63, 70 ,77, 84 this is the answer