Question

5. The sum of the digits of a two digit number is 10 and the digit at units place is 2/3 rd of the digit
at tens place. Find the number.​

Answer 1

Step-by-step explanation:

please see the attachment

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Answer 2

Step-by-step explanation:

let the digit at 10th place =3x

then the digit at one’s ploace=3x*2/3=2x

sum of the digits

=2x+3x=10

5x=10,x=2

so digit at 10s place=3x=6

digit at one’s place=2x=4

hence the number=64

Therefore the required number is 64