Question

5. The sum of two numbers is 80 and the greater number exceeds twice the s
by 11. Find the numbers. N
6. Find three consecutive odd natural numbers whose sum is 87.​

Answer 1

Answer:

5) x + (2x + 11) = 80

    x + 2x + 11 = 80

    3x + 11 = 80

    x = (80 - 11)/3

    x = 69/3

    x = 23

    2x + 11 = 57

the 2 nos are 23 and 57

6) x + (x+2) + (x+4) = 87

    x + x + 2 + x + 4 = 87

    3x + 6 = 87

     x = (87 - 6)/3

     x = 81/3

     x = 27

     x + 2 = 29

     x + 4 = 31

the three consecutive odd numbers are 27, 29, 31

PLS MARK AS BRAINLIEST

Answer 2

Answer:First let me do N6

Step-by-step explanation:3consecutive numbers

First you need to know the odd numbers and these are 1,3,5,7,11 and so on then you need to know the natural numbers which arejust the normal counting numbers 123456.......so then you need to know the method to calculate coz you won't say that such and such a no. when added is 87 so the method used is

let x be the first consecutive no.

let x+1 be the secondno.

let x+3 be the third consecutive off natural number

then you say x+x+3+x+5=87

collect like terms

x+x+x+3+5=87

3x +8=87

3x+8-8=87-8

3x=79

x=26.3