Question

in a 2-digit number , ten's digit is twice the unit digit . if the sum of the digits is 6 find the number .​

Answer 1

Sᴏʟᴜᴛɪᴏɴ :-

Let us Assume That, Required two digit number is (10x + y) , where ,

→ Ten's digit = x

→ unit digit = y .

Now, we have given that, ten's digit is twice the unit digit.

So,

→ Ten's digit = 2 * unit digit

→ x = 2y -------------- Eqn.(1)

And, we also have given that, sum of the digits is 6.

So,

→ x + y = 6 -------------- Eqn.(2)

Putting Eqn(1) value in Eqn.(2) , we get,

→ 2y + y = 6

→ 3y = 6

→ y = (6/3)

→ y = 2.

Putting This value in Eqn.(1) Now,

→ x = 2y

→ x = 2*2

→ x = 4.

Therefore,

→ Required Two digit Number is = (10x + y) = 10*4 + 2 = 40 + 2 = 42 (Ans.)

Hence, The Number is 42.

Answer 2

Given:

in a 2-digit number , ten's digit is twice the unit digit

To find:

if the sum of the digits is 6 find the number .

STEP BY STEP EXPLANATION:

$\implies$Refer to the attachment

the Number is 42

Hence verified !1