Question

5. The volume of certain mass of a gas at of 400K and pressure 202600 Pascal is 2 cubic metres. What would be the volume of the gas at 3270C and 152 cm of Hg pressure ? [ 101300 Pascal = 760 mm of Hg pressure]​

Answer 1

Answer:

Correct option is

C

11×10

4

J

Solution:

PV=nTR

⇒10×

5

×1=n(83.14)×300

⇒n=

(83.14+300)

10

5

∴n=40

change in internal energy is given as 10

4

Joule

⇒du=10

4

=

n

C

V

dT

[pressure is constant so,vαTv

1

=v and v

2

=2v so, T

1

=300kT

2

=600k

Now, Heat supplied=dθ=

n

C

p

dT

=n(C

v

+R)dT

=40(8.21+0.833)×(600−300)

=40(9.043)×300

=110000j

=11×10

4

j

Explanation:

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