*In a circle with center ' P ' chord AB = chord CD. If chord AB is at a distance of 2.8 cm from the center of the circle then find the distance of chord CD from the center of the circle.*
1️⃣ 2.8 cm
2️⃣ 1.4 cm
3️⃣ 5.6 cm
4️⃣ 4.2 cm
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Answer:
2.8 cm is the distance of chord CD from the centre of the circle
Step-by-step explanation:
I think so
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Concept: In circle, If length of chords are equal then these chords are equidistant from the center.
Given: AB=CD
Distance of AB from center= 2.8 cm
Find: Distance of CD from the center of circle
Solution: According to the above theorem, chord AB and CD are equidistant from the center.
Therefore, distance of CD from the center of the circle is 2.8 cm
Final answer: option 1 is correct 2.8cm
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