Question

5. There are some *2 coins and some 5
coins in an urn. Total number of coins is
100 and total value of the coins is 380.
Find the number of each type of coins. Solve
the equations by the cross-multiplication
method.​

Answer 1

Ya sure.

Let the total number of coins be 12X.

Then,

Number of Rs.5 coins = 3X

Number of Rs.2 coins = 4X

Number of Re.1 coins = 5X

Total value of :-

Rs.5 coins = 3X * 5 = 15X

Rs.2 coins = 4X * 2 = 8X

Re.1 coins = 5X * 1 = 5X

Given, total value of all coins = 224

Therefore,

15X + 8X + 5X = 224

28X = 224

X = 8

Total number of coins = 12X = 12 * 8 = 96

Number of,

Rs.5 coins = (3/12) * 96 = 24 coins

Rs.2 coins = (4/12) * 96 = 32 coins

Re.1 coins = (5/12) * 96 = 40 coins

(Given no. of Rs.5, Rs.2, and Re.1 coins are in the ratio of 3:4:5)

Final Answer : The boy has 40 Re.1 coins.

Let's cross verify the answer once.

(24*5) + (32*2) + (40*1)

= 120 + 64 + 40

= 224 = Value given in the question.

Step-by-step explanation:

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