Question

5.There are two numbers such that sum of the numbers is 50 and the difference is 14 . Find the difference of their cubes.

Answer 1

Step-by-step explanation:

Let the no. be x and y

x+ y= 50. (1)

x-y= 14

x=14+y. (2)

put 2 in 1

14+y+y= 50

14+2y= 50

2y= 36

y= 18

x+y=50

x+ 18= 50

x= 32

a3-b3= (a-b) (a2+b2+ab)

= (32-18)[(18)^2 +(32)^2 + (32)(18)]

= 14[ 324 +1024 + 576]

= 14(1924)

= 26936

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Answer 2

Answer:

take first no. as - x

take second as - y

then, x + y = 50

and, y = 50 - x

and, x - y will be = 14

place y's expandation in place of y that is, 50 - x

so, it will become = x - ( 50 - x ) = 14

= x - 50 + x = 14

= 2x - 50 = 14

= 2x = 50 + 14 = 64

= x = 64/2 = 32

and, y = 50 - x = 50 - 32 = 18

cube of 32 = 32768

cube of 18 = 5832

their difference = 32768 - 5832 = 26936