5. Three resistance are connected as shown in the
figure Through the resistance 5 ohms a current
1 ampere is flowing.
a) What is the current through the other two resistance
B) what is the pd across AB and across CD
c) What is the total resistance
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Answer:
Given,
Current in AC, I
AC
=1A
Resistance in BC, R
BC
=
10+15
10×15
=6Ω
Current flowing in series I
AB
=I
BC
=1A
V
BC
=I
BC
×R
BC
=1×6=6V
In parallel potential is equal
V
BC
=I
10
R
10
=I
15
R
15
=6
(a) I
10
=
10
6
=0.6A, I
15
=
15
0.6
=0.4A
(b) Potential in AB V
AB
=I
AB
R
AB
=1×5=5V., V
BC
=I
BC
R
BC
=1×6=6V
(c) Total Resistance R
total
=R
AC
+R
BC
=5Ω+6Ω=11Ω
→11 ohms .
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