5 To cross-roads each of width 5 m run at right angles through the centre of a rectangular park 70 m
by 50 m, such that each is parallel to one of the sides of the park. Find the area of the remaining portion
of the park.
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Step-by-step explanation:
let the one path ABCD
let the second path EFGH
let the common part of both path PQRS
find the area of one path=5*70=350m^2
find the area of second path=5*50=250m^2
find the area of common= 5*5=25m^2
area of the path=area of ABCD+area of EFGH-area of PQRS
=350+250-25=575m^2
thus, the area of the path is 575m^2
Area of rectangular park=30*20=600m^2
remaining portion=area of park - area of path
= 600-575= 25m^2
thus, the remaining portion is 25m^2
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