Question

5. Two Coins are tossed together find the
probability of
A)
Two head
6) one head
c) No tail​

Answer 1

Answer:

5 A HHhh 4/4

hhHH 4/4

6 ht 1/2

th1/1

Answer 2

B=getting 2 heads

B=(HHT,HTH,THH) n(B) =3

p(B)= n(B)/n(s)=3/8

b) getting one head

(TTT)n(E) =1

p(E) = n(E)/ n(s)=1/8

c) H=(HHH) n(H) =1

p(H) =n(H) /n(s) =1/8