5. Two dice are thrown
simultaneously. What is the
probability that the sum of the
numbers appearing on the dice
is: (i) 7 (ii) 12
Answer:
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Answer:
1.
- 1,6
- 2,5
- 3,4
- 4,3
- 5,2
- 6,1
6/36
=1/6
2.
- 6,6
1/36
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Answer:
Step-by-step explanation:
Total number of outcomes = n = 36
Let A be the event that sum on the dice is 7.
=> (4,3) (3,4) (5,2) (2,5) (6,1) (1,6)
= m = 6
P(A) = m/n = 6/36 = 1/6
Less than or equal to 12
Total number of outcomes =36
Probability that sum of two numbers is less than or equal to 12 =
Total no. of outcomes
No. of outcomes where sum is less than or equal to 12
= 36/36
=1
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