Question

5. Two forces each of
magnitude 10 N act
vertically upwards
and downwards
respectively at the
two ends A and B
of a uniform rod of length 4 m which is pivoted at its mid point O determine te magnitude of moment of forced about the pivot O.​

Answer 1

Answer:

40Nm

Explanation:

Magnitude of force applied on each end = 10 N .

The moment of force τ = r × F. Hence in bothe the cases, moment of force is in the clockwise direction, and the moment of forces add to one another. 

The magnitude of τ = 2 × 10 × 2 = 40 Nm in the clockwise direction.

Answer 2

Answer:

Magnitude of force applied on each end = 10 N .

The moment of force τ = r × F. Hence in bothe the cases, moment of force is in the clockwise direction, and the moment of forces add to one another.  

The magnitude of τ = 2 × 10 × 2 = 40 Nm in the clockwise direction

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