5. Two pieces of length 2y metres and x metres respectively were cut off from
the ends of a rope that was originally 5x metres long.
57 metres
21 metres
x metres
What was the length of the remaining piece?
B. 3x metres
A. 2x meters
C.(5 - 2y) metres
D. (4x - 2y) metres
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Answered by
2
Answer:
Given
Total length of the rope =11 m
If the rope is cut into 3 pieces
Length of the first piece = 2 3/5=13/5 m
Length of the second piece =3 3/10=33/10 m
We have to find out length of the third piece =x
x= total length -(length of the first piece + length of the second piece)
=11 - (13/5+33/10)
=11-[(26+33)/10]
=11/1 - 59/10
=(110-59)/10
=51\10
=5 1/10 m
Therefore
Length of the remaining piece =x =5 1/10 m
Step-by-step explanation:
Answered by
0
Answer:
d
Step-by-step explanation:
4x subract 2yTwo pieces of length 2y metres and x metres respectively were cut off from
the ends of a rope that was originally 5x metres long.
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