Math, asked by kirthanb12, 5 hours ago

5. Two pieces of length 2y metres and x metres respectively were cut off from
the ends of a rope that was originally 5x metres long.
57 metres
21 metres
x metres
What was the length of the remaining piece?
B. 3x metres
A. 2x meters
C.(5 - 2y) metres
D. (4x - 2y) metres
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Answers

Answered by ananya2006sri
2

Answer:

Given

Total length of the rope =11 m

If the rope is cut into 3 pieces

Length of the first piece = 2 3/5=13/5 m

Length of the second piece =3 3/10=33/10 m

We have to find out length of the third piece =x

x= total length -(length of the first piece + length of the second piece)

=11 - (13/5+33/10)

=11-[(26+33)/10]

=11/1 - 59/10

=(110-59)/10

=51\10

=5 1/10 m

Therefore

Length of the remaining piece =x =5 1/10 m

Step-by-step explanation:

Answered by shesanthvelvijayan0
0

Answer:

d

Step-by-step explanation:

4x subract 2yTwo pieces of length 2y metres and x metres respectively were cut off from

the ends of a rope that was originally 5x metres long.

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