Question

5)Two resistances of 5 ohm and 12 ohm are
connected in parallel, and bulb of 2 ohm is
connected in series with both. Find the ratio
of power dissipated in them if battery across
circuit is made of 3 cells of 20 volt​

Answer 1

Explanation:

(a) Req =

3+2

3×2

=

5

6

=1.2Ω

(b) V=IR⇒I=

R

V

⇒I=

1.2

12

=10A

(c) 3(10−i)=2i (∵ Potential drop in parallel combination are same)

⇒30−3i=2i⇒30=5i⇒i=6A

Current in 2Ω resistor is =i=6A

Current in 3Ω resistor is =10−i=4A