Question

5 under root + 3 under root / 5 under root - 3 under root
is equal x

Answer 1

ans may be ......... x = 1

Answer 2

$\frac{ \sqrt{5} + \sqrt{3} }{ \sqrt{5} - \sqrt{3} } = x \\ \frac{ \sqrt{5} + \sqrt{3} }{ \sqrt{5} - \sqrt{3} } \times \frac{ \sqrt{5} + \sqrt{3} }{ \sqrt{5} + \sqrt{3} } = x \\ \frac{( \sqrt{5} ) ^{2} +( \sqrt{3} ) ^{2} + 2 (\sqrt{5})( \sqrt{3} )}{( \sqrt{5}) ^{2} - ( \sqrt{3}) ^{2} } = x \\ \frac{5 + 3 + 2 \sqrt{15} }{5 - 3} = x \\ \frac{8 + 2 \sqrt{15} }{2} = x \\ \frac{2(4 + \sqrt{15}) }{2} = x \\ 4 + \sqrt{15 } = x$