Math, asked by adarshgamerxmx, 17 days ago

(5+underoot 5) (5- underoot 5)​

Answers

Answered by IIRissingstarll
22

\huge\sf\fbox\blue{✬ Äñswêr ✬}

(5 +  \sqrt{5} )(5 -  \sqrt{5} )

5(5 -  \sqrt{5} ) +  \sqrt{5} (5 -  \sqrt{5} )

25 - 5 \sqrt{5}  + 5 \sqrt{5}  - 5

 = 25 - 5

 = 20

\huge\sf\fbox\purple{or}

Using identity

(a + b)(a - b) =  {a}^{2}  -  {b}^{2}

(5 +  \sqrt{5} )(5 -  \sqrt{5} ) =  {5}^{2}  -  ({ \sqrt{5} })^{2}

25 - ( \sqrt{5}  \times  \sqrt{5} )

 = 25 - 5

 = 20

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