Question

Factorise: 27p3
– 64q3​

Answer 1

Answer:

(3p + 4p).(9p^2 - 12pq + 16q)

Step-by-step explanation:

we need to apply the formula of a^3 -b^3

=a3 - b3 = (a - b) (a2 + ab + b2)

here $3\sqrt27p^3$ =3p and

$3\sqrt64q3$ = 4q

so a= 3p and b= 4q now replace a and b with the values in the formula:

a^3 -b^3

=a3 - b3 = (a - b) (a2 + ab + b2)

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