Math, asked by dhruti3, 11 months ago

5 upon minus7 plus root3 want answer

Answers

Answered by goyalvikas78
1
Hey there!

 \frac{5}{ - 7 +  \sqrt{3} }   \\  \frac{5}{ \sqrt{3 }  - 7 }  \times  \frac{ \sqrt{3} + 7 }{ \sqrt{3} + 7 }  \\ \frac{5 \sqrt{3} + 35 }{( { \sqrt{3)} }^{2}  -  {(7)}^{2} }  \\  \frac{5 \sqrt{3 }  + 35}{3 - 49}  \\  \frac{5 \sqrt{3}  + 35}{ - 46}  \:  \:  \: or \:  \:  \:   \frac{ - 5 \sqrt{3}  - 35}{46}
Hope it help
Answered by codiepienagoya
0

Simplify:

Step-by-step explanation:

\ Given \ Value: \\\\ \frac{5}{-7+\sqrt{3}} \\\\\ Solution: \\\\\frac{5}{-7+\sqrt{3}} \\\\\ rationalizing \ the \ given \ number: \\\\\rightarrow \frac{5}{-7+\sqrt{3}} \times \frac{-7-\sqrt{3}}{-7-\sqrt{3}}\\\\\rightarrow \frac{5(-7-\sqrt{3})}{(-7+\sqrt{3})(-7-\sqrt{3})} \\\\\rightarrow \frac{(-35-5\sqrt{3})}{(-7+\sqrt{3})(-7-\sqrt{3})} \\\\\rightarrow \frac{(-35-5\sqrt{3})}{((-7)^2-(\sqrt{3})^2)} \\\\\rightarrow \frac{(-35-5\sqrt{3})}{(49-3)} \\\\\rightarrow \frac{(-35-5\sqrt{3})}{(46)} \\\\

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