Question

5. What is the acceleration produced by a force of 12 N exerted on a 3 Kg mass of an object?

Answer 1

$\huge\underline\mathcal\blue{Solution-}$

We know that,

$Force=mass×accelation$ [ By second law of motion ]

$F=ma$

Given that, force = 12 N and mass = 3 kg

Now, put the given values in above formula.

=> $12=3a$

=> $a=\dfrac{12}{3}$

=> $a=4$

Therefore, acceleration = 4 m/s²

____________________________

Answer 2

$\Huge{\red{\underline{\underline{\rm{ANSWER}}}}}$

$\large\bold{\purple{\underline{\textsf{What is acceleration? }}}}$

$\blacksquare$ Acceleration is defined as the change in rate of velocity.

$\blacksquare$ S.I unit of acceleration is $m/s^{-2}$

$\Huge{\underline{\underline{\rm{Question}}}}$

What is the acceleration produced by a force of 12 N exerted on a 3 Kg mass of an object?

$\Huge{\underline{\underline{\rm{Solution}}}}$

$\Huge{\red{\underline{\mathtt{Given}}}}$

$\large{\orange{\underline{\textsf{Force\:is\:12\:N}}}}$

$\large{\orange{\underline{\textsf{Mass\:is\:3\:kg}}}}$

$\Huge{\red{\underline{\mathtt{To\:find}}}}$

$\large{\orange{\underline{\textsf{Acceleration\:?}}}}$

NOW

FORCE=MASS x ACCELERATION

a=$\dfrac{F}{m}$

a=$\dfrac{</strong><strong>1</strong><strong>2</strong><strong>}{</strong><strong>3</strong><strong>}$

a=4

$\Huge{\red{\underline{\textsf{</strong><strong>A</strong><strong>c</strong><strong>c</strong><strong>e</strong><strong>l</strong><strong>e</strong><strong>r</strong><strong>a</strong><strong>t</strong><strong>i</strong><strong>o</strong><strong>n</strong><strong> </strong><strong>is </strong><strong>4</strong><strong> </strong><strong>m</strong><strong>/</strong><strong>s</strong><strong>^</strong><strong>{</strong><strong>-</strong><strong>2</strong><strong>}</strong><strong> </strong><strong>}</strong><strong>}}}$