Question

5. What is the activation energy for a reaction if its rate
doubles when the temperature is raised form 20°C to 35°C
(R = 8.314 J mol-'K-)
INEET)
(a) 342 kJ mol-1
(b) 269 kJ mol-1
(c) 34.7 kJ mol-1
(dy51.1 kJ mol-1​

Answer 1

Answer:

log

k

1

k

2

=

2.303×R

E

a

(

T

1

1

−

T

2

1

)

Substituting the values

log 2 =

2.303×8.314

E

a

(

293

1

−

308

1

)

E

a

=34.7 kJ mol

−1