Question

5. What should be added to 5a” + 2ab to get 3a- 4ab?
6.Find the excess of 7xyz2 + 6cd + 3c over 2xyz" + 3cd + c?
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Answer 1

Step-by-step explanation:

5) Soln: Let x to be added,

x + (5a +2ab) = (3a - 4ab)

=> x = (3a - 4ab) - (5a + 2ab)

= -2a - 6ab

= -(2a + 6ab)

so, -(2a + 6ab) should be added.

6) Soln : let the y be the excess,

Now,

(7xyz + 6cd + 3c) - y = (2xyz + 3cd + c)

=> y = (7xyz + 6cd + 3c) - (2xyz + 3cd + c)

= 5xyz + 3cd + 2c

So, (5xyz + 3cd + 2c) is the excess.

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