Question

5. When 147 is divided by N the remainder is 4
When 255 is divided by N the remainder is 8
When 622 is divided by N the remainder is 11
Find N?; 5. When 147 is divided by N the remainder is 4; When 255 is divided by N the remainder is 8; When 622 is divided by N the remainder is 11; Find N?

Answer 1

Answer: 13

Step-by-step explanation:

When 147 is divided by N the remainder is 4

When 255 is divided by N the remainder is 8

When 622 is divided by N the remainder is 11

So N is a factor of 143, 247 and 611

143 = 13 x 11

247 =  13 x 19

611 = 13 x 47

So HCF is 13

N = 13

Answer 2

if 147 is divided by N the remainder is 4

a=bq+r(euclids division lemma)

147=11×N+4

11×N=147-4 [q=quotient]

11×N=143 (r=remainder)

N=143/11 (a=divident)

N=13 (b=divisor)

Same for all

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