Question

(5) Which are the zeroes of p(x) =x² -1​

Answer 1

Answer:

x=1,-1

Step-by-step explanation:

p(x)=x²-1

x²-1=0

(x-1)(x+1)=0   {(a+b)(a-b)=a²-b²}

x-1=0 x=1

x+1=0 x=-1

zeroes are x=1,-1