Math, asked by abhishek009547, 5 hours ago

Find the value of a and bif 3+ √2 3-√2 = a + √2b.​

Answers

Answered by vikalppandey242
1

Answer:

a=5 b=0

Step-by-step explanation:

a=3. b=√2.

(a+b)(a-b)=a^2-b^2

(3+√2)(3-√2)=3^2-√2^2

9-4=a+√2b

5=a+√2b

compairing rational with rational and irrational with irrational

a=5. b=0

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