Find the value of a and bif 3+ √2 3-√2 = a + √2b.
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Answer:
a=5 b=0
Step-by-step explanation:
a=3. b=√2.
(a+b)(a-b)=a^2-b^2
(3+√2)(3-√2)=3^2-√2^2
9-4=a+√2b
5=a+√2b
compairing rational with rational and irrational with irrational
a=5. b=0
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