Question

hi brainly amitnrw Sir please solve this sum​

Answer 1

Explanation:

Solution

e=velocity of separation (after collision)velocity of approach (before collision)

=(v2−v1)(u1−u2)=(v2−v1)(u1−0)=(v2−v1)u1

⇒v2−v1=eu1 (1)

From the law of conservation of linear momentum,

μ1=mv1+mv2⇒u1=v1v2 (2)

Using the equation (2) for u1 in (1), we get

v2−v1=e(v1+v2)

On simplification, we get

v1v2=1−e1+e n o so rr y rea lly i don't under stand

Answer 2

Answer:

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