Math, asked by GR8ANSH, 1 month ago

5. Which of the following represents the set B = {x:x is an interger, x^2+ 1 = 10)?

(A) B = {3}
(B) B-{-3,3}
(C)B- { }
(D) B-{-3, ..., 3}​

Answers

Answered by pushkarajpuranik2003
1

Answer:

B

Step-by-step explanation:

put the values of option into the question, Or solve the quadratic eq

x^2=10-1

x^2=9

x=√9

x=+-3

Answered by narendrkumar42
1

Answer:

(B) B = {-3,3}

Step-by-step explanation:

To find Set B we have to solve the equation

 {x}^{2} + 1 = 10

Now,

 {x}^{2}  + 1 = 10 \\  {x}^{2} + 1 - 10 = 0 \\  {x}^{2}  - 9 = 0 \\  {x}^{2} -  {3}^{2}  = 0 \\

This is in the form of

 {a}^{2}  -  {b}^{2}  = (a + b)(a - b)

So,

 {x}^{2}  -  {3}^{2}  = 0 \\ (x + 3)(x - 3) = 0 \:  \:  \:  \\ so \:  \: either \:  \: x - 3 = 0 \:  \: or \:  \: x + 3 =0 \\ x = 3 \:  \:  \: or \:  \: x =  - 3

So, Set B = {-3,3}

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