Question

5. Write the smallest digit and the greatest digit in the blank space of each of the following
numbers so that the number formed is divisible by 3:
(a) _ 6724 (b) 4765 __ 2​

Answer 1

Answer:

a)...+6+7+2+4=...+19 = 2+19=21÷3

So smallest number =2

& ...8..+19 =27 is divisible by 3

so greatest number = 8

b) 4+7+6+5 +...+2=24+.3..= 27÷3

so smallest number = 3

& ...9. +24 =33 is divisible by 3

so greatest number = 9