Math, asked by mohdziahanmohdzishan, 8 months ago

5. Write the smallest six-digit number and express it as a product
6. Write the largest four-digit number and find its prime factors.
7. Find the H.C.F. of the following numbers by prime factorization​

Answers

Answered by Anonymous
16

Answer:

5. the smallest 6 digit number is 100000 and same prime factor.

6. Greatest 4 digit number is 9999 its prime factors are ××11 × 101

Step-by-step explanation:

Factorization is as follows:-

9999 = 3×3333,,,,, 3333 = 3×1111,,,,,1111 = 11×101,,,,,,,, 101 = 101×1.

Answered by RvChaudharY50
7

Solution :-

5)

→ Smallest six-digit number = 1,00,000

writing it in product of prime factors we get,

→ 100000 = 2 * 2 * 2 * 2 * 2 * 5 * 5 * 5 * 5 * 5 = 2⁵ * 5⁵ .

6)

→ Largest four digit number = 9999

now, prime factors of 9999 are :-

→ 9999 = 3 * 3 * 11 * 101

Learn more :-

let a and b positive integers such that 90 less than a+b less than 99 and 0.9 less than a/b less than 0.91. Find ab/46

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