Math, asked by khushnuma78666, 1 year ago

5(x-1)+2(x+3)+6=0 solve and verify

Answers

Answered by piyush03
61
hola mate
this is your answer

5x-5+2x+6+6=0
5x+2x-5+12=0
7x+7=0
7x= -7
x= -7/7
x= -1

putting value of x in the given equation
5(-1-1)+2(-1+3)+6=0
5(-2)+2(2)+6=0
-10+4+6=0
-10+10=0
0=0

hence proved

plzz mark as brainliest
Answered by Choudharipawan123456
3

Answer:

=> x = -1

Step-by-step explanation:

Given that:-

5(x-1)+2(x+3)+6=0

To find:- The value of the expression,

In order to solve that, we have to use the concept of BODMAS:

As we have,

=> 5(x-1)+2(x+3)+6=0

Distribute the terms:

=> 5x-5+2x+6+6=0

Add the terms:

=> 5x+7+2x=0

Combine the terms:

=> 7x+7=0

Subtract 7 on both sides:

=> 7x+7-7=0-7

=> 7x=-7

Divide both sides by 7, we get

=> x = -1

Hence, the required solution is -1.

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