5(x+2)^2+6(x+2) +1 find factor
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_________________________
5 ( x + 2 )^2 + 6 ( x + 2 ) + 1
= 5 ᴀ^2 + 6 ᴀ + 1 [ • ʟᴇᴛ ( x + 2 ) = ᴀ ]
= 5 ᴀ^2 + 5 ᴀ + ᴀ + 1
= 5ᴀ ( ᴀ + 1 ) + 1 ( ᴀ + 1 )
= ( ᴀ + 1 ) ( 5ᴀ + 1 )
= ( x + 2 + 1 ) ( 5x + 10 + 1 ) [ • ᴘᴜᴛᴛɪɴɢ ᴛʜᴇ ᴠᴀʟᴜᴇ ᴏғ ᴀ ]
= ( x + 3 ) ( 5x + 11 )
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★ ᴅᴇᴠɪʟ ᴋɪɴɢ
ʜᴇʀᴇ's ʏᴏᴜʀ ᴀɴsᴡᴇʀ
_________________________
5 ( x + 2 )^2 + 6 ( x + 2 ) + 1
= 5 ᴀ^2 + 6 ᴀ + 1 [ • ʟᴇᴛ ( x + 2 ) = ᴀ ]
= 5 ᴀ^2 + 5 ᴀ + ᴀ + 1
= 5ᴀ ( ᴀ + 1 ) + 1 ( ᴀ + 1 )
= ( ᴀ + 1 ) ( 5ᴀ + 1 )
= ( x + 2 + 1 ) ( 5x + 10 + 1 ) [ • ᴘᴜᴛᴛɪɴɢ ᴛʜᴇ ᴠᴀʟᴜᴇ ᴏғ ᴀ ]
= ( x + 3 ) ( 5x + 11 )
________________________
ʜᴏᴘᴇ ɪᴛ ʜᴇʟᴘs ʏᴏᴜ ᴅᴇᴀʀ!
★ ᴅᴇᴠɪʟ ᴋɪɴɢ
rajdevisingh:
answer is (5x+11) (x+3)
It means you are fool
Put the value of a in following answer
a=x+2
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