Math, asked by surajkumbaj, 1 year ago

5^x-3*3^2x-3=225, find the value of x​

Answers

Answered by amar1325
5

Step-by-step explanation:

we are given this equation.

we have to find the value of x.

5^(x-3) × 3^(2x-3)= 225

we are going to break down 225 by prime factorization first.

5^(x-3) × 3^(2x-3) = 5 × 5  × 3 × 3

5^(x-3) × 3^(2x-3) = 5² × 3²

so clearly we see x-3 must be equal to 2 and 2x-3 must be equal to 2.

x-3=2

x=2+3

x=5

now,

2x-3=2

2x=2+3

x= 5/2

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